Zend_Controller_Front::getInstance()->getParam('bootstrap')->getResource('Cache');
But I like
$cache = Zend_Registry::get('Zend_Cache);
it's shorter.
Regards,
Saša Stamenković
Regards,
Saša Stamenković
On Tue, Nov 17, 2009 at 8:34 AM, Nick Pack <nick@nickpack.com> wrote:
This is probably a dumb question, but I'm looking for a way to call a bootstrap resource from a model (in this case is a Zend_Cache object).
Bootstrap method:
protected function _initCache()
{
$frontendOptions = array(
'lifetime' => 7200, // cache lifetime of 2 hours
'automatic_serialization' => true
);
$cachedir = realpath(/path/to/cache');
$backendOptions = array(
'cache_dir' => $cachedir
);
$cache = Zend_Cache::factory('Core',
'File',
$frontendOptions,
$backendOptions);
Zend_Registry::set('Zend_Cache',$cache);
return $cache;
}
Obviously this is set into the registry so I can access it that way, but I was wondering if this is the best way to do it, or whether there was some way of calling it like you do in a controller:
$this->_cache = $this->getInvokeArg('bootstrap')->getResource('Cache');
or maybe even passing it directly over to the __construct of the model.
Any advice greatly appreciated
没有评论:
发表评论