Re: [fw-gdata] Working with Multi-page Feeds Google Provisioning API

On Tue, Nov 17, 2009 at 1:30 PM, Hugo León <hugolec@gmail.com> wrote:

Hello again Ryan.

I decided to leave this issue until the end because it was difficult to
perform. I have now reached the point where this is the only thing missing
to complete the system.

I did what you suggested:

while ($feed !== null) {
 foreach ($feed as $user) {
   echo "<tr>";
   echo "<td>".$user->login->username."</td>";
   echo ""</tr>;  }

*  $feed = **$feed->getNextFeed();**
}

And what it does is that it shows all records of the feed exactly as
retrieveAllEntriesForFeed() instruction. But what I want to do is break them
into pages.

There's an atom:link element with a rel='next' that contains the link for the next step of results.  Instead of $feed->getNextFeed(), you can instead call $feed->getNextLink()->getHref(), which will be the URL for the next step of results.  You can see the format for the provisioning API-- it just uses the next username in the feed for paging.

Are there some examples for this task?

The closest examples are to retrieve 100 users starting at a particular username:

http://code.google.com/apis/apps/gdata_provisioning_api_v2.0_reference_php.html#Retrieve_100_Users_in_Domain_Example

Of course, you'll need to know the next username-- though you could always use the last username you saw and then just ignore the first result.  However, I think the getNextLink method will work better.

Cheers,

-Ryan

 

Best regards.
Hugo

Ryan Boyd-3 wrote:
>
> When you echo out the previous and next URLs, what do you get?  You won't
> be
> able to click on it and see it (because you wouldn't be sending the
> appropriate auth credentials), but you should be able to retrieve that
> feed.
>
> The following two blocks of code should be identical:
> ---
> while ($feed !== null) {
>   foreach ($feed as $user) {
>     echo "<tr>";
>     echo "<td>".$user->login->username."</td>";
>     echo ""</tr>;  }
> *  $feed = **$feed->getNextFeed();**
> }*----
> ---
> while ($feed !== null) {
>   foreach ($feed as $user) {
>     echo "<tr>";
>     echo "<td>".$user->login->usern"</td>";
>     echo ""</tr>;  }
> *  $feed = **$feed->getUserFeed($nextLink);*
> }----
>
> On Wed, Oct 21, 2009 at 4:34 PM, Hugo León <hugolec@gmail.com> wrote:
>
>>
>> Hello Ryan.
>>
>> For now I'm getting in the same manner the feed to the next page, but the
>> URL that I've got is
>>
>> https://apps-apis.google.com/a/feeds/domain.com/user/2.0?startUsername=username
>> and when I click it can't see the next page of the feed.
>>
>> What I do not want to do is show all the entries because we have one
>> GApps
>> domain with about 2,000 users, just as you recommended me.
>>
>> Here is the code:
>>
>> Zend_Loader::loadClass('Zend_Gdata');
>> Zend_Loader::loadClass('Zend_Gdata_ClientLogin');
>> Zend_Loader::loadClass('Zend_Gdata_Gapps');
>> Zend_Loader::loadClass('Zend_Gdata_Feed');
>>
>> //ClientLogin
>> function getClientLoginHttpClient($user, $pass)
>> {
>>  try{
>>        $service = Zend_Gdata_Gapps::AUTH_SERVICE_NAME;
>>        $client = Zend_Gdata_ClientLogin::getHttpClient($user, $pass,
>> $service);
>>        return $client;
>>  } catch (Zend_Gdata_App_AuthException $e) {
>>
>>  }
>> }
>>
>> $client = getClientLoginHttpClient($admin."@".$domain, $gappspass);
>> $gapps = new Zend_Gdata_Gapps($client, $domain);
>> $feed = $gapps->getUserFeed();
>> $previousLink = $feed->getLink("previous");
>> $nextLink = $feed->getLink("next");
>>
>> foreach ($feed as $user) {
>> echo "<tr>";
>> echo "<td>".$user->login->username."</td>";
>> echo ""</tr>;
>> }
>> if ($previousLink !== null) {
>>  echo "previous url: " . $previousLink->href . "<br />";
>>  $previousFeed = $gapps->getUserFeed($previousLink->href);
>> }
>> if ($nextLink !== null) {
>>  echo "next url: " . $nextLink->href . "<br />";
>>  $nextFeed  = $gapps->getUserFeed($nextLink->href);
>> }
>>
>> Where should I put '$feedWithNextPageOfEntries = $feed->getNextFeed();' ?
>> or
>> how should I call it?.
>>
>> Thanks in advance.
>> Hugo
>>
>>
>> Ryan Boyd (Google) wrote:
>> >
>> > You probably have an existing $feed variable with the feed of results.
>> >
>> > Try:$feedWithNextPageOfEntries = $feed->getNextFeed();
>> > If you have a $service and an existing $feed and want to retrieve ALL
>> > entries (can be expensive), you can do:
>> > $feedWithAllEntries = $service->retrieveAllEntriesForFeed($feed);
>> >
>> > Cheers,
>> > -Ryan
>> >
>> > On Tue, Oct 13, 2009 at 2:56 PM, Hugo León <hugolec@gmail.com> wrote:
>> >
>> >>
>> >> Hello everyone.
>> >> I'm trying to get all users of a Google Apps domain and does it well.
>> >> But when there are domains with more than 100 users appear only the
>> first
>> >> 100, and with the function that comes into Zend website gives me the
>> link
>> >>
>> >>
>> https://apps-apis.google.com/a/feeds/domain.com/user/2.0?startUsername=username
>> >> ,
>> >> but obviously when I click on that link it does not work because I
>> need
>> >> authorization via ClientLogin again. And what I want to do is that it
>> >> only
>> >> shows me the next 100 users.
>> >>
>> >> How can I do this?
>> >> Thanks in advance.
>> >>
>> >> Hugo
>> >> --
>> >> View this message in context:
>> >>
>> http://www.nabble.com/Working-with-Multi-page-Feeds-Google-Provisioning-API-tp25881614p25881614.html
>> >> Sent from the Zend gdata mailing list archive at Nabble.com.
>> >>
>> >>
>> >
>> >
>>
>> --
>> View this message in context:
>> http://www.nabble.com/Working-with-Multi-page-Feeds-Google-Provisioning-API-tp25881614p26001897.html
>> Sent from the Zend gdata mailing list archive at Nabble.com.
>>
>>
>
>

--
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