Re: [fw-gdata] Working with Multi-page Feeds Google Provisioning API

When you echo out the previous and next URLs, what do you get?  You won't be able to click on it and see it (because you wouldn't be sending the appropriate auth credentials), but you should be able to retrieve that feed.

The following two blocks of code should be identical:

---

while ($feed !== null) {

  foreach ($feed as $user) {
    echo "<tr>";
    echo "<td>".$user->login->username."</td>";
    echo ""</tr>;

  }

  $feed = $feed->getNextFeed();
}

----

---

while ($feed !== null) {

  foreach ($feed as $user) {
    echo "<tr>";
    echo "<td>".$user->login->usern"</td>";
    echo ""</tr>;

  }

  $feed = $feed->getUserFeed($nextLink);
}

----

On Wed, Oct 21, 2009 at 4:34 PM, Hugo León <hugolec@gmail.com> wrote:

Hello Ryan.

For now I'm getting in the same manner the feed to the next page, but the
URL that I've got is

https://apps-apis.google.com/a/feeds/domain.com/user/2.0?startUsername=username

and when I click it can't see the next page of the feed.

What I do not want to do is show all the entries because we have one GApps
domain with about 2,000 users, just as you recommended me.

Here is the code:

Zend_Loader::loadClass('Zend_Gdata');
Zend_Loader::loadClass('Zend_Gdata_ClientLogin');
Zend_Loader::loadClass('Zend_Gdata_Gapps');
Zend_Loader::loadClass('Zend_Gdata_Feed');

//ClientLogin
function getClientLoginHttpClient($user, $pass)
{
 try{
       $service = Zend_Gdata_Gapps::AUTH_SERVICE_NAME;
       $client = Zend_Gdata_ClientLogin::getHttpClient($user, $pass, $service);
       return $client;
 } catch (Zend_Gdata_App_AuthException $e) {

 }
}

$client = getClientLoginHttpClient($admin."@".$domain, $gappspass);
$gapps = new Zend_Gdata_Gapps($client, $domain);
$feed = $gapps->getUserFeed();
$previousLink = $feed->getLink("previous");
$nextLink = $feed->getLink("next");

foreach ($feed as $user) {
echo "<tr>";
echo "<td>".$user->login->username."</td>";
echo ""</tr>;
}
if ($previousLink !== null) {
 echo "previous url: " . $previousLink->href . "<br />";
 $previousFeed = $gapps->getUserFeed($previousLink->href);
}
if ($nextLink !== null) {
 echo "next url: " . $nextLink->href . "<br />";
 $nextFeed  = $gapps->getUserFeed($nextLink->href);
}

Where should I put '$feedWithNextPageOfEntries = $feed->getNextFeed();' ? or
how should I call it?.

Thanks in advance.
Hugo

Ryan Boyd (Google) wrote:
>
> You probably have an existing $feed variable with the feed of results.
>
> Try:$feedWithNextPageOfEntries = $feed->getNextFeed();
> If you have a $service and an existing $feed and want to retrieve ALL
> entries (can be expensive), you can do:
> $feedWithAllEntries = $service->retrieveAllEntriesForFeed($feed);
>
> Cheers,
> -Ryan
>
> On Tue, Oct 13, 2009 at 2:56 PM, Hugo León <hugolec@gmail.com> wrote:
>
>>
>> Hello everyone.
>> I'm trying to get all users of a Google Apps domain and does it well.
>> But when there are domains with more than 100 users appear only the first
>> 100, and with the function that comes into Zend website gives me the link
>>
>> https://apps-apis.google.com/a/feeds/domain.com/user/2.0?startUsername=username
>> ,
>> but obviously when I click on that link it does not work because I need
>> authorization via ClientLogin again. And what I want to do is that it
>> only
>> shows me the next 100 users.
>>
>> How can I do this?
>> Thanks in advance.
>>
>> Hugo
>> --
>> View this message in context:
>> http://www.nabble.com/Working-with-Multi-page-Feeds-Google-Provisioning-API-tp25881614p25881614.html
>> Sent from the Zend gdata mailing list archive at Nabble.com.
>>
>>
>
>

--
View this message in context: http://www.nabble.com/Working-with-Multi-page-Feeds-Google-Provisioning-API-tp25881614p26001897.html

Sent from the Zend gdata mailing list archive at Nabble.com.